`1, sqrt 2, sqrt 3, 2` Find the general term.



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Posted on (Answer #1)

`1, sqrt2, sqrt3, 2`

To determine the general term, express the four terms as radicals.


`1=sqrt1` and `2 =sqrt4`

then the sequence becomes:

`sqrt1, sqrt2, sqrt3, sqrt4`

Next, consider the numbers inside the square root.

`a_1 = 1`      `a_2= 2`      `a_3=3`      `a_4=4`

Then, determine if they have common difference.




Since they have common difference, apply the formula of arithmetic series in solving for nth term.


Plug-in `a_1=1` and d=1.



`a_n= n`

Since we only consider the number inside the square root, to determine the nth term of the given sequence, take the square root on `a_n` .

`a_n= sqrtn`

Hence, the general term of  `1, sqrt2, sqrt3, 2`  is   `a_n=sqrtn` .

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