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How many moles of nitric acid are in 5.3 mL of 13 M nitric acid? Please explain.
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Molarity can be expressed as moles per liter of solution We can simply write it as:
Molarity = moles/ Volume of solution (in liters)
In the problem we are looking for the amount of moles in the solution.We can solve that if we transform the equation as:
moles = Molarity x Volume of solution(L)
Molarity = 13 (M or moles/L)
Volume = 5.3mL
**notice that The volume is in mL so we have to convert mL to L first before proceeding to the next step.
1L = 1000mL
5.3 mL x 1L/1000mL = 0.0053L
Now we can solve the number of moles:
moles nitric acid = 13moles/L x 0.0053 L
= 0.0689 moles nitric acid
= 0.069 or 6.9x10^-2 moles nitric acid
Posted by jerichorayel on October 18, 2012 at 4:00 AM (Answer #1)
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