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How many moles of nitric acid are in 5.3 mL of 13 M nitric acid?   Please explain.

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polvorizer | Student, College Freshman | eNotes Newbie

Posted October 18, 2012 at 2:12 AM via web

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How many moles of nitric acid are in 5.3 mL of 13 M nitric acid? 

 

Please explain.

Tagged with chemistry, molarity, science

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jerichorayel | College Teacher | (Level 1) Senior Educator

Posted October 18, 2012 at 4:00 AM (Answer #1)

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Molarity can be expressed as moles per liter of solution We can simply write it as:

Molarity = moles/ Volume of solution (in liters)

In the problem we are looking for the amount of moles in the solution.We can solve that if we transform the equation as:

moles = Molarity x Volume of solution(L)

Given:

Molarity = 13 (M or moles/L)

Volume = 5.3mL

**notice that The volume is in mL so we have to convert mL to L first before proceeding to the next step.

1L = 1000mL

5.3 mL x 1L/1000mL   = 0.0053L

 

Now we can solve the number of moles:

moles nitric acid  = 13moles/L x 0.0053 L

                          = 0.0689 moles nitric acid

                          = 0.069 or 6.9x10^-2 moles nitric acid


 


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