(1)graph the equation g(x)=1/3-1/4x

(2)describe and correct the error,given the functions f(x)=3x-5and g(x)=1/3-4/3x. (a)f(5)=3(5)-5 (b)g(0)=1/3-4/3

5f=15-5 =-3/3

5f=10 =-1

f=2

### 1 Answer | Add Yours

#1) Graph the equation `g(x) = 1/3 - 1/4x`

y-intercept = `(0, 1/3)`

slope = `-1/4`

#2)

a: `f(x) = 3x - 5`

To find f(5) means to substitute 5 for x. The error is that f was treated as a variable to solve for. f is not a variable, it is notation for a function.` `

`f(5) = 3(5) - 5`

` ` `f(5) = 15 - 5`

`f(5) = 10`

b: `g(0) = 1/3 - 4/3x`

Substitute 0 for x.

`g(0) = 1/3 - 4/3(0)`

` ` `g(0) = 1/3 - 0`

`g(0) = 1/3`

The mistake is that 0 was not multiplied by 4/3. It was treated as nothing and just takin away.

**Final answer:**

`f(5) = 10` and `g(0) = 1/3`

` `

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