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The reaction between `MnO_4^-` and `Sn^(2+)` is as follows. This is also described http://www.enotes.com/homework-help/0-472-g-sample-an-alloy-tin-bismuth-dissolved-444120#answer-626430
`2MnO_4^(-)+16H^++5Sn^(2+) rarr 2Mn^(2+)+8H_2O+5Sn^(2+)`
The titration has takes place with 0.0107M `KMnO_4 ` and 15.61ml was consumed for the reaction.
Amount of `KMnO_4` used `= 0.0107/1000xx15.61 = 1.67xx10^-4 `
So `1.67xx10^-4` `MnO_4^- ` moles has used in the average titration.
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