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A 0.239 g sample of a gas in a 100-mL flask exerts a pressure of 600 mmHg at 14 °C....
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We can use the Ideal gas law here
`1mmHg = 1.316*10^-3 atm`
`PV = nRT`
`P=600xx1.316xx10^3 =0.79 atm`
`T=273+14 = 287K`
So the gas could be Nitrogen Or `N_2` .
Posted by jeew-m on August 24, 2013 at 3:23 AM (Answer #1)
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